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6n^2+54n+48=0
a = 6; b = 54; c = +48;
Δ = b2-4ac
Δ = 542-4·6·48
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-42}{2*6}=\frac{-96}{12} =-8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+42}{2*6}=\frac{-12}{12} =-1 $
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